Y^3+11y^2=26y

Solution for Y^3+11y^2=26y equation:

^3+11Y^2=26Y

We move all terms to the left:

^3+11Y^2-(26Y)=0

We add all the numbers together, and all the variables

11Y^2-26Y=0

a = 11; b = -26; c = 0;
Δ = b2-4ac
Δ = -262-4·11·0
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-26}{2*11}=\frac{0}{22}
=0
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+26}{2*11}=\frac{52}{22}
=2+4/11
$